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Mathematics problems in grade three
Let the side length be x, cf = y and ce = z.

According to Pythagorean theorem:

x^2+(x-y)^2=25

x^2+(x-z)^2= 16

y^2+z^2=4

From the first two equations, the solutions of y and z are represented by x, and if you substitute into the third equation, you can get x 2.

The expression solution of x 2: x 2 (41-2x2+2 √ (x4-41x 2+400))-342.25 = 0.

But the back is very troublesome.