(1) If x≥y, the absolute value is: x-y =-xy.

That is xy+x-y = 0, (x-1) (y+1) =-1.

Because both X and Y are integers, X- 1 = 1, Y+ 1 =- 1 or X- 1 =- 1, Y+1=/kloc.

Solution: x = 2, y =-2 or x = 0, y = 0.

(2) if x < y, then: -x+y=-xy.

That is xy-x+y = 0, (x+1) (y-1) =-1.

Because both X and Y are integers, X+ 1 = 1, Y-1=-kloc-0/or X+1=-kloc-0/,Y-1=/kloc.

Solution: x = 0, y = 0 (discarded because x < y is irrelevant) or x =-2, y = 2.

So there are three groups of integer solutions: x = 2, y =-2 or x = 0, y = 0 or x =-2, y = 2.