Update 1: Not every copy must be the same.

That means: cut one knife: 2+2 cut two knives: 4+4 cut three knives: 8+6 cut four knives: 14+8 cut five knives: 22+ 10 cut six knives: 32 ... = 2+(2+n) * (n/2)/ ) * (n/2)/2 = 2+n/2+n 2/4 This is wrong. If you use 6 knives to cut the fruit, use 5 knives to tie it, 1 knife column, so it is 32 pieces -(5 * 6/2+ 1).

But you can bevel, which means: 4 knives +2 knives, and the face of 4 knives can have a bevel of 1 1 2 knives.

That's what it means: plan:-| \/|| | | | |/|||-| and11* 4 = 44, but it can cut the cake into 7 * 7 = 49 and 5: 4 * 7 = 24.

When you cut four knives,

There's 16. Cut it five times.

There are 28 pieces cut 6 times.

There are 49-I hope I can help you _-when you have questions in this answer.

You can send me a letter. -Bye! 2010-08-0817: 45: 32 supplement:-| \/|||| |||||||||||||||||||||| | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |

Calculate the angle and length of the cake 2010-08-0914:15: 42 Supplement: Because according to your cutting method, when cutting 4 knives, there are at most 4×4 cakes ... but in fact, only 12 pieces can be cut (I don't believe it. Because the cakes on the surface are different in size, they may not overlap when cutting columns. ...

I can have 16 yuan.

Reference: I hope I can help you _

I hope I can help you _

4g 5 tablets, 6g 6 tablets, 5g 5 tablets, 8g 8 tablets, 6g 5 tablets 10 tablets.

Reference: I

Can't draw = = cut 1 knife, there are 2 pieces, 2 pieces at most, 4 pieces at most, 3 pieces at most, 8 pieces at most (1 middle of tool rest), 4 pieces at most, 14 pieces at most (3 pieces at most. 7 pieces) and 1 tool rest upstairs have been solved), 5 pieces, 2 pieces are possible. 4*4 = 16 block or you can cut it three times and waste it twice -> 7*3 = 2 1 block or you can have four cutting faces (maximum. 1 1 block) and 1 tool rest -> 1 1*2 = 22 blocks ... Let x be the cutting times.

F(x) is the number of cakes.

Varies with the top and middle cuts.

G(x) is the number of cuts at the top. G (1) = 2 =1+1g (2) = 4 =1+1+2g (3) = 7 =1+.

F (1) = g (1) = 2f2 = g (2) = 4f (3) = g (2) * 2 = 4 * 2 = 8f (4) = g (3) * 2 = 7 * 2 =/.

It can be g(6)

g(5)*2

g(4)*3

G (3) * 4...etcbur for max。 F (6) = g (4) * 3 = (4 * 5/2+1) * 3 = 33 There are at most 33 six cutters, four cutter faces and two cutter posts 20 10-08-0620. G (x) is the number of cakes cut on it. 20 1 0-08-0621:49: 32 supplement: if the fruit is cut with 6 knives, it should be tied with 5 knives and1knife. It's 32 pieces -(5 * 6/2+ 1) * 2, but cutting four knives is 1 1 piece, and adding two knives is 33 pieces -(4 * 5. When the binding surface is punched, you can cut 4 pieces diagonally. The ................................................................................................................................................................... should be close to 49 pieces-7 * 7. This problem is really deep = = 2010-08-0818: 09: 47 Supplement: Songxian County, Fu Lin: The diagonal cutting in the middle of the column is not necessarily the most, because according to your cutting method, when cutting 4 knives, there are at most 4×4 cakes ... but in fact, only/kloc-can be cut out. Due to the different sizes of the cake, it may be impossible to overlap a cover when cutting the chromatographic column ... 2010-08-0818:13: 56558. For example, if you cut six knives, the seven pieces cut on the surface are different sizes, indicating that it is difficult to cut in the middle of the column.

Reference: a wild guess

Hello ~ ~ After reading this topic and one of the netizens' comments in the comment column, I think the answer should be this: Picture reference: i820.photobucket/albums/zz127/urine147/3644f3b8 In the above picture, we can cut three knives on it first, which has been divided into seven unequal parts, and then cut one knife from the middle of the cake, which is seven. I drew a little quirk in the picture above. As long as I draw better, I can get seven cakes. Because I can have different shapes, I deserve fourteen cakes. I hope I can help you ~ ~ ~ 2010-08-0519. Supplement: According to Xiaoyi Wen's opinion, it is not difficult to get: (cut n knives on [surface]) You can get two pieces by cutting one knife (zero knives+/kloc-). Photo bucket/Albums/ZZ127/urine147/779eb318 The simple picture is as follows: "Slant knife cuts twice, front cuts twice", four in the middle, four in the front and sixteen in the burial. 2010-08-0818: 21:55 supplement: after cutting five knives, you can cut six knives, just like Lin Songxian said: if you cut three knives in the middle, you will get (2x2)(7) = 28 pieces of six knives, and you will get three knives in the face. 20 1 0-08-0918: 32: 33 supplement:1knife: 2x 1 knife: 2x2 knife: 4x2 knife: 4x4 knife: 7x4 knife: 65433 knife. 11x11cutter 9:11cutter1cutter:16x1cutter. 4->； 7 is from "1+[n (n+1)]/2"1+0.5 [n x (n+1)].

Reference: yogi bear

Let's draw a picture. Primary school teachers like me very much ... every line should be cut as much as possible, so that it can be cut four times at most and eleven times at most.

I only know that three knives can cut eight knives. 2010-08-0517: 28: 26 Supplement: Do you want the same amount of each cake?