(1) according to the meaning of the question, A=2.
2π/w=(π/2)×2
The solution is w=2.
So f(x)=2sin(2x- π/6)+ 1.
(2)a∈(0, π/2), then a/2∈(0, π/4)
2=f(a/2)
=2sin(a -π/6)+ 1
That is sin(a- π/6)= 1/2.
a- π/6=π/6
So a=π/3
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