1. If f (x) = x- 1x+ 1, then f (2) = f(2)=.
a . 1b . 12c . 13d . 14
The analytic f (2) = 2-12+1=13.x.
Answer c
2. The following groups of functions, said the same function is ().
A.y = x- 1,y = x2- 1x+ 1。
B.y = x0 and y = 1
C.y = x2,y = (x+ 1) 2。
D.f(x)=? x? 2x and g (x) = x? x? 2
In analysis a, the domain of Y = X- 1 is r, while the domain of Y = X2- 1x+ 1 is {x | x ≠1};
The function y = x0 in b defines the domain {x|x≠0}, while y = 1 defines the domain as r;
The analytical expressions of the two functions in C are different;
The domains of f(x) and g(x) in d are both (0, +∞), and after simplification, F (x) = 1 and G (x) = 1, so they are the same function.
Answer d
3. Fill the bottle with water in the shape shown in Figure 2-2- 1 at a fixed speed, and the relationship between the water surface height h and the time t is ().
Figure 2-2- 1
It is analyzed that the height h of water surface increases with the increase of time t, and the increasing speed is faster and faster.
Answer b
4. The domain of the function f (x) = x- 1x-2 is ().
A.
D ..
answer
7. The domain of the function y = 3 1-x- 1 is _ _ _ _ _.
In order for the function to be meaningful, the independent variable x must satisfy
x- 1≥0 1-x- 1≠0
Solution: x≥ 1 and x≠2.
The domain of ∴ function is [1, 2)∞(2, +∞).
Answer [1, 2)∩(2, +∞)
8. Let the function f (x) = 4 1-x, if f (a) = 2, the real number A = _ _ _ _ _ _
If f (a) = 2, it is 4 1-a = 2 and the solution is a =- 1.
Answer-1
Third, answer questions.
9. The function f (x) = x+ 1x is known.
Find the domain of (1) function f(x);
(2) the value of f (4).
The solution (1) is x≥0, x≠0, x >;; 0, so the domain of the function f(x) is (0,+∞).
(2)f(4)= 4+ 14 = 2+ 14 = 94。
10. Find the domain of the following function:
( 1)y =-x2 x2-3x-2; (2)y=34x+83x-2。
For the solution that (1) makes y =-x2x2-3x-2 meaningful, it must be -x ≥ 0, 2x2-3x-2 ≠ 0, and the solution is x≤0, x ≦- 12.
Therefore, the domain of the function is {x|x≤0, x≦- 12}.
(2) In order to make y = 34x+83x-2 meaningful,
Must be 3x-2 >;; 0, namely x & gt23,
Therefore, the domain of the function is {x | x >;; 23}.
1 1. It is known that f (x) = x2 1+x2, x∈R,
(1) Calculate the value of f (a)+f (1a);
(2) Calculate the value of f (1)+f (2)+f (12)+f (3)+f (13)+f (4)+f (14).
Solution (1) Because F (a) = A2 1+A2, f (1a) =1+a2,
So f (a)+f (1A) = 1.
(2) Method 1 is because f (1) =121+12 =12, and f (2) = 221+22 = 12? 2 1+? 12? 2= 15,f(3)=32 1+32=9 10,f( 13)=? 13? 2 1+? 13? 2= 1 10,f(4)= 42 1+42 = 16 17,f( 14)=? 14? 2 1+? 14? 2= 1 17,
So f (1)+f (2)+f (12)+f (3)+f (13)+f (4)+f (14) =12.
Method 2 (1) shows that f (a)+f (1a) = 1, then f (2)+f (12) = f (3)+f (13).
And f (1) = 12, so f (1)+f (2)+f (12)+f (3)+f (13)+f (4)+.