Test analysis: (1) Carefully analyze the meaning of the question and make a judgment according to the nature of folding and the definition of "good angle";

(2) Because ∠BAC is a good angle of △ABC after three folds, ∠A 2 B 2 C=∠C is ∠ ABB 1 = ∠ AA 1 for the third fold. And ∠ a1b1c = ∠ a1a2b2, ∠ A 1A2B2 = ∠ A2B2C2C+∠ C, ∠ ab/.

(3) Because the minimum angle is 4? It's a good angle for △ABC. According to the definition of good angle, the other two angles can be set to 4m? ，4mn？ (where m and n are positive integers), from the meaning of the question, 4m+4mn+4= 180, so m(n+ 1)=44. According to the fact that both m and n are positive integers, we can get the result that both m and n+ 1 are integer factors of 44.

(1) From the meaning of the question, ∠BAC is a good corner of △ABC;

(2) Because ∠BAC is a good angle of △ABC after the third discount, ∠A 2 B 2 C=∠C after the third discount.

Because ∠ abb1= ∠ aa1b1,∠ aa1b1= ∠ a1b.

So ∠ abb1= ∠ a1b1c+∠ c = ∠ a2b2c+∠ c+∠ c = 3 ∠ c.

It can be guessed that if ∠BAC is a good angle of △ABC after n times, ∠ B = n ∠ C;

(3) Because the minimum angle is 4? Good angle △ABC,

According to the definition of good angle, the other two angles can be set to 4m? ，4mn？ (where m and n are positive integers).

From the meaning of the question, 4m+4mn+4= 180, so m (n+ 1) = 44.

Because both m and n are positive integers, both m and n+ 1 are integer factors of 44.

So there are: m= 1, n+1= 44; m=2，n+ 1 = 22； m=4，n+ 1 = 1 1； m= 1 1，n+ 1 = 4； m=22，n+ 1=2。

So m= 1, n = 43m=2, n = 21; m=4，n = 10； m= 1 1，n = 3； m=22，n= 1。

So 4m=4, 4mn =172; 4m=8，4mn = 168； 4m= 16，4mn = 160； 4m=44，4mn = 132； 4m=88，4mn=88。

So the degrees of the other two angles of the triangle are: 4? , 172? ; 8? , 168? ; 16? , 160? ; 44? , 132? ; 88? ,88? .

Comments: This kind of problem is the key and difficult point of junior high school mathematics, which is very common in the senior high school entrance examination.