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An inequality problem in the seventh grade of mathematics! ! ! ! Good answer points! ! !
Suppose a car needs x cars and a car needs y cars, then there are

45x+60y=270

y-x= 1，

45x+60( 1+x)=270 is used to solve the equation.

45x+60+60x=270

105x=270-60=2 10

It is found that x=2 y=x+ 1=3, so a car needs 2 cars and a car needs 3 cars.

Freight: 350 * 2+400 * 3 = 700+1200 =1900 yuan.

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