{ z = √(x? + y? )
{ z? = 2x
x? + y? ≤ 2x
(x - 1)? + y? ≤ 1, the area d projected on the xoy plane
√[ 1 + (? z/? x)? + (? z/? y)? ] = √[ 1 + x? /(x? + y? )+ y? /(x? + y? )] = √[2(x? + y? )/(x? + y? )] = √2
Surface area =∫∫σdS
= ∫∫D √2 dxdy
= √2∫(- π/2→π/2) dθ ∫(0→2cosθ) r dr
= 2√2(0→π/2)【r? /2]|(0→2cosθ) dθ
= 2√2∫(0→π/2) ( 1/2) * 4cos? θ dθ
= 4√2 * 1/2 * π/2
= √2π