Then due to the over point (3, 2)

So you can get y=kx+2-3k.

Then because m and n are on the x-axis and y-axis respectively, OQ=QP,

So if m and n don't coincide with point o,

MONP is square.

So the abscissa of point p is the same as that of point m. The ordinate is the same as the ordinate of point n.

Because M(3K-2/K, 0) n (0,2-3k)

Therefore, the coordinates of point p can be expressed by K.

When k is eliminated, Y=2x/(x-3).

If the points m, n and o coincide,

So X=Y=O

According to the above equation

Satisfy the equation

Therefore, the locus of point P is y=2x/(x-3).