Then due to the over point (3, 2)
So you can get y=kx+2-3k.
Then because m and n are on the x-axis and y-axis respectively, OQ=QP,
So if m and n don't coincide with point o,
MONP is square.
So the abscissa of point p is the same as that of point m. The ordinate is the same as the ordinate of point n.
Because M(3K-2/K, 0) n (0,2-3k)
Therefore, the coordinates of point p can be expressed by K.
When k is eliminated, Y=2x/(x-3).
If the points m, n and o coincide,
So X=Y=O
According to the above equation
Satisfy the equation
Therefore, the locus of point P is y=2x/(x-3).