We can have X sheep, so when the sales price is the same as the number of sheep, we can get the payment of X * X Of course, we can divide X into two parts, that is, let x= 10y+z, where z is a number. In this way, suppose that x*x can be transformed into: (10y+z)*( 10y+z), and after expansion: (10y+z) * (10y+z) =/kloc-0.

And100y 2 can always be divisible by 2, and 20y is an even number, so it can always be divisible by 2. Let's look at the situation of z*z:

Z can be any value between 0 and 9, and 0*0=0.

1* 1= 1

2*2=4

3*3=9

4*4= 16

5*5=25

6*6=36

7*7=49

8*8=64

9*9=8 1

As there is less than 10 yuan left in the end, it is B's turn to get it, so the result of z*z needs to meet the conditions: 1. If there are ten digits, the ten digits need to be odd. 2, the unit is not equal to 0 3, it must have ten digits, otherwise the last part will be taken away by A.

It can be seen that the Z that can meet the requirements may be: 4 or 6. Whether z is 4 or 6, the unit number of z*z is 6. In order for Party A and Party B to get the same money, Party A needs to allocate 2 yuan to Party B. ..