Analysis: Question 1: Suppose four people are A, B, C and D, and the cards written are A, B, C and D. Starting from A, it is easy to get three ways to go A. Suppose A goes B, and then analyze the number of ways to go B. The remaining two people have only one way to go. According to the principle of step-by-step counting, the answer can be obtained.

According to the meaning of the question, list all the results and you can get the answer.

Answer:

Suppose four people are a, b, c and d, and the cards written are a, b, c and d,

Since everyone has to take what others have written, that is, they can't take what they have written, there are three ways to get an A,

Suppose a takes b, then b can take any of the remaining three cards, there are three ways to take it, and only one can take c and d,

So * * * has 3×××/kloc-0 /×1= 9 distribution patterns. Question 2: You missed it. I wonder how many boys there are. Suppose there are four. Then: (1): Choose 2 men and 2 women from 4 men and 4 women. According to the combination principle, C42*C42=36.

(2): Choose 4 men and 2 women, and choose 2 out of 8-2=6, that is, C62= 15.

(3): With reverse thinking, because there is at least one of A among boys and B among girls, it is assumed that both A and B among boys are not selected, and all cases * * * have C84 kinds, and both A and B are not selected, so there are four of the remaining six people with C64 kinds, so there is at least one of A among boys and B among girls, and C84-C64= 55.

(4): Using the method of the third question, assuming that there are only boys or girls with C44+C44=2 cases, then there are boys and girls with C84-2=68 cases.