Haven't you mastered the relationship between the roots and coefficients of a quadratic equation and the maximum value of a quadratic inequality? The answer is here. See for yourself ... /exercise/math/798988 Let me sum up the relationship between the roots of a quadratic equation and the discriminant △: ①△ > 0 equation has two unequal real roots; ② The δ = 0 equation has two equal real roots; ③△& lt； Equation 0 has no real root.

According to the meaning of the question, △ = b 2-4ac > =0, and then calculate according to the minimum value of inequality.

The final answer is 5/4.

If the equation x 2+2mx+m 2+3m-2 = 0 has two real roots x 1, x 2, then the minimum value of x1(x2+x1)+x2 2 is _ _ _ _ _.

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