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mathematical problem
1. 1 truck 1 secondary coal transportation 120/6/5=4t and 13 truck's 4 coal transportation 13*4*4=208t.

2. Method 1: 1 truck 1 secondary coal transport 120/6/5=4t, then 8 trucks transport coal for 6 times 8*4*6= 192t.

Method 2: add three or two trucks, which is 3/5 of the original. If the delivered quantity remains unchanged, the coal transportation will increase 120*3/5=72.

Total * * * coal transportation 120+72= 192.

3. If Party A produces 2 less than Party B per hour, it will produce 6 * 2 less than Party B within 6 hours =12.

Party A produces 8 hours, Party B produces 6 hours, and Party A produces 88 more than Party B, so Party A must produce 88+ 12= 100 in two hours, and 100/2=50 B = 52 per hour.

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