Current location - Training Enrollment Network - Mathematics courses - Mathematical problems of beer bottle cap
Mathematical problems of beer bottle cap
Twenty bottles. Oh, I already have one.

1.2 yuan 1 bottle of wine, 1 bottle of 4 caps, 1 bottle of 2 bottles. The calculation is: 1 bottle cap 0.5 yuan, 1 bottle 1 yuan, 1 bottle of purified beer = 2-0.5-65438+.

2. 10 yuan buys 5 bottles of beer, 5 bottles with 5 caps for 3 bottles of wine residue 1 bottle 1 cap, 4 bottles with 4 caps for 3 bottles of wine, 3 bottles with 3 caps for 1 bottle 1 cap, and 2 bottles with 4 caps for 1 bottle of wine. Borrow 1 bottle of wine and drink ***2 bottles and 4 lids just for 2 bottles of wine, borrow 1 bottle of wine and drink 2 bottles and 2 lids, borrow 1 bottle of wine and drink 1 bottle of wine, leaving 2. * * * Number of drinking bottles = 5+3+3+1+2+1+2+1+kloc-0/+2-2 = 20 bottles of wine.