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There is a math problem that is a bit difficult. Please help me solve it. This requires a process.
Suppose there are x peaches in this box.

A There are peaches: 1/4x+7.

B There are peaches: 1/5x+5.

C There are peaches:1/2 (x-1/4x-7-1/5x-5).

The remaining peaches: 1/8X

Relationship: A+B+C+ surplus = a box of peaches.

1/4X+7+ 1/5X+5+ 1/2(X- 1/4X-7- 1/5X-5)+ 1/8X = X

9/20X+ 12+ 1/2(X-9/20X- 12)+ 1/8X = X

18/40X+ 1 1/40X+5/40X+ 12-6 = X

34/40X+6=X

6=X-34/40X

x = 6 \6/40

X=40

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