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The math problem in senior one is a bit difficult to kneel on.
Solution:

By the way, s? = 3/4 inch? x

In triangle ABP, it is determined by cosine theorem: (AP? +AB? -PB? )/(2*AP*AB)=cosx

So, PB? =4-2√3cosx

In triangle PBQ, cosine theorem: (PQ? +BQ? -PB? )/(2BQ*PQ)=cosQ

So cosQ=√3cosx- 1.

So, sin? Q= 1-cos? Q=2√3cosx-3cos? x

t? =( 1/2PQ*PB)? = 1/4sin? Q=√3/2cosx-3/4cos? x

So, s? +T? =√3/2cosx-3/4cos? x+3/4sin? x

=√3/2cosx-3/4cos? x+3/4-3/4cos?

=3/4-3/2cos? x+√3/2cosx

(Think of it as a quadratic function)

To sum up: if and only if cosx=√3/6, s? +T? Take the maximum value. 7/8 at most.