(x-2)^2+(y-2)^2= 1

∴⊙∵ C is symmetric about X, and X is the center of the circle of∵∵≉≈≈≈≈≈≈≈≉≉≉≉≉𕛡≉𕛡≉𕛡≉󖓑8777

Let the equation of the line where the ray L is located be y=k(x+3)+3, that is, kx-y+3(k+ 1)=0.

From the meaning of the question, the straight line where the light L is located is tangent to ⊙C'

∴|2k+2+3(k+ 1)|/√(k^2+ 1)= 1

Solve to get k=-4/3 or k=-3/4.