Set two turntables, namely turntable A and turntable B.. The probability in turntable A is P(A)=20%, and the miss probability is 1-p (a) = 80%.

The probability in turntable B is P(B)=20%, and the miss probability is 1-P(B)=80%.

Judging from the meaning of the question, turntable A and turntable B are independent of each other and will not affect each other.

Therefore, the winning probability of mode 2 is p = p (a) p (b)+p (a) [1-p (b)]+[1-p (a)] p (b) = 34%.

Therefore, the winning probability of mode 1 and mode 2 is different, and the winning probability of mode 2 is even smaller.