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Seek the detailed explanation of Chongqing senior high school entrance examination mathematics 10.
Choose D.

1, ① The option is correct.

∠∠ea b+∠BAP = 90,∠BAP+∠PAD=90 ,∴∠EAB=∠PAD

* AE = AP,AB=AD,∴△APD≌△AEB.

2.② Wrong option.

The distance from b to AE is the distance from d to AP;

∵△APD?△aeb, ∴∠ABE=∠ADE,∴∠BED=∠BAD, that is, EB⊥ED (option ③ authentication).

∵EP=√2,BP=√5,∴EB=√3=PD

S _ (△ APD) =1/2×√ 3×√ 2/2 = √ 6/4 =1/2× AP× h, and the distance from ∴D to AP = √ 6/2.

∴ The distance from B to AE is also ∴ 6/2;

3. The correctness of option ③ has been proved in the previous proof;

4.④ Wrong option

s_(△apd)=√6/4,s_(△ape)= 1/2,∴s_(△apd)+s_(△ape)=√6/4+ 1/2;

5. The options are correct.

∵BE=√3,ED=√2+√3,∴BD=√(8+2√6),

∴S_(□ABCD)=4+√6

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