(1) According to f(2)=- 1, we can make f( 1-x)=f(2), get the solution of x=- 1, and bring it into f (1-x) =-

Substituting two sets of values into xf(x)=b+cf(x), b-c=- 1 and b+c=0, the solution is: b=- 1/2, c= 1/2, so f (x) = 65438.

(2)f(x) monotonically increases from negative infinity to 1/2 in X and from 1/2 to positive infinity in X. ..

(3)f(x)= 1/( 1-2x)( 1

f(x)=x+2 (2

From (1 and (2 simultaneous 1/( 1-2x)=x+2, the solution is: x1=-3/4+17 (1/2).

X2 =-(3+17 (1/2))/4, Y2 = (5- 17 (1/2))/4, point (x 1, y65438+. From this, we can calculate the triangle area: S= 1/2*L*D, and get the solution: S = 17 (1/2)/2, that is, 17 under the root sign divided by 2.