8× 125-40X = 600 0.4x÷5 = 0.6 2X+0.82 = 0.82 3+0.5X = 7
x+80×2 = 200 45-2X = 10+ 15 8×2.5-4x = 18 6÷( 1.5+x)= 1.5
4+x+3.9 = 15. 1x-0. 13-7.5 = 3.24 7.5×4.2-6x = 1.5 7.8x-x-6.6 = 7
0.5X+4 = 6 9.5x-5x = 13 3X+2.4 = 2.4 80x÷4 = 12
The problem and answer of the 50-solution equation of Hundred Regiments War is a sabotage operation (also known as guerrilla warfare in southern Shanxi) launched by the18th Army of the National Revolutionary Army (hereinafter referred to as the Eighth Route Army) during the War of Resistance against Japanese Aggression period in China from August 1940 to August 194 1 day, aiming at destroying the traffic lines and mines occupied by Japanese troops in North China. China's participating troops include the Eighth Route Army120th Division and129th Division, the Shanxi-Chahar-Hebei Military Region and local militia. It was also a large-scale battle that the Eighth Route Army participated in after the Pingxingguan campaign. At the beginning of the war, the statistics of the Battle Report (the first stage) reached 105 regiments, so it was named Hundred Regiments Battle (formerly Zheng Tai Campaign). This work has also been adapted into a film of the same name.
50 solutions (0.5+x)+x = 9.8 ÷ 22 (x+x+0.5) = 9.8 25000+x = 6x3200 = 450+5x+x-0.8x = 612x-8x = 4.8. 2X = 15 1.2x = 8 1.6x+5.6 = 9.4 52-X = 15 9 1÷X = 1.3x+8.3 = 10.7 15x = 3 3x-8 = / kloc-0/6 7(X-2)= 2X+3 3x+9 = 1 = 5.8 65x+7 = 42 9x+4×2.5 = 9 1 4.2x+2.5x = 134 10.5 X+6.5 X = 5 1 89x-43x = 9.2 5x-45 = 100 1.2x-0.5x = 6.3 23.4 = 2X = 56 4x 3 x÷0.5 = 2.6 x+ 13 = 33 3-5x = 80 1 .8+6x = 54 6.7 x-60.3 = 6.7 9+4x = 40 2x+8 = 16 x/5 = 10 x+7x = 8 9x-3x = 6 6x-8 = 4 5x+x = 9 x-8 = 6 x4/ 5x = 20 7x-8 = 4 3x-8 = 30 6x+6 = 12 3x-3 = 1 5x-3x = 4 2X+ 16 = 19 5x+8 = 19 14-6x = 8 15+6x = 27 5-8x = 4 7x+8 = 15 9-2X = 65438
Give you the answer? Nice try!
The speed is 10 to solve the equation calculation problem, "important process! ~ answer! @ 1 A student walked from home to school for 2 minutes at a speed of 50 meters per minute. If he goes like this, he will be eight minutes late. Later, he moved at a speed of 60 meters per minute, and he arrived at school five minutes early. How far is the student's home from the school?
50(X+8)=60(X-5)
X=70
50(X+8)=50*78=3900 meters The distance from the students' home to the school is 3900 meters.
A project needs to be completed within the specified time. If 6 people are reduced, the working hours will be increased 12 days; If the number of workers increases by four, the working hours will be reduced by four days. Try to find the stipulated time and the original number of people? (solved by binary linear equation)
X people, y days:
XY =(X-6)(Y+ 12)= XY-6Y+ 12X-72
XY =(X+4)(Y-4)= XY+4Y-4X- 16
X= 16 people Y=20 days.
Party A and Party B set out from Party A and Party B at the same time, and the first meeting was more than 50 meters away from the midpoint. After Party A and Party B arrive at Party B, they immediately turn around and go back. So, Party A and Party B met for the second time at a distance of 0/00 meters from Party A/KLOC-to find out the distance between Party A and Party B. ..
Let the distance between Party A and Party B be X, and when they meet for the second time, the distance they walked is three times that of the first time. A:
(2X- 100)/3=X/2+50
X=500 meters
A shop bought two baskets of apples, A and B, weighing 200 Jin. If you take out 1 1 from the first basket and put it in the second basket, then the first basket is less than the second basket 165438+2+0. How many kilograms of apples are there in baskets A and B?
x+y=200
10x/ 1 1:(y+x/ 1 1)= 9/ 1 1: 1
99y= 10 1x
X=99 kg A。
Y= 10 1 kg B。
It takes 6 days for Party A, Party B and Party C to cooperate to complete a project. Now Party A and Party B cooperate 1 day, and then Party C works alone for 8 days. What is the function of C?
1/x+ 1/y+ 1/z = 1/6
1/x+ 1/y+8/z = 1
Z=8.4 days
C it takes 8.4 days to do it alone.
17 There are strange stones every other meter on the straight line. We should concentrate the stones in the middle, starting with the correct stones, and only move one stone at a time in order. If someone moves stones like this, all the stones are concentrated in the middle except the one in the middle, and * * * walks 300 meters. * * *, how many stones have been put?
Let * * have 2X+ 1 pebble, then move the pebble of the rightmost pebble, walk x meters, follow it to the position of X- 1 on the right, and then walk 2(X- 1) meters to the position between them, and so on, and move all the pebbles on the right:
X+2[(X- 1)+(X-2)+...+2+ 1]=x+2*[(x- 1)+ 1](x- 1)/2=x+x(x- 1)=x^2
It takes x meters to move the stone on the left than to move the stone on the right, but it takes 2X meters to move the stone on the left (it takes x meters to move the stone on the right), so all the stones on the left are moved by x 2+X.
X^2+X^2+X=300
X^2+X/2= 150
X= 12
2X+ 1=25 *** There are 25 stones.
19 the passenger ship sailed from port a to port b, and the cargo ship sailed from port b to port a, and the two ships sailed opposite each other, meeting 10 hour, and then continuing to drive for 3 hours. At this time, the passenger ship is 280 kilometers away from Port B, and the cargo ship is 420 kilometers away from Port A. How many kilometers are there between Port A and Port B?
Solution: If the sum of the speeds of passenger ships and cargo ships is A, then the meaning of the question is:
10a = 3a+280+420 Solution: A = 100 So the distance between port A and port B is10×100 =1000 km.
20 A to b is a ramp. The car goes up the hill at 30 kilometers per hour and down the hill at 45 kilometers per hour. It takes three hours to go back and forth. How many kilometers is it between A and B?
Let the distance of 2 be x.
It takes X/30 to climb a mountain.
The downhill time is X/45.
X/30+X/45=3
The solution is X=54.
2 1 Express, China and slow three start from the same place at the same time and catch up with the cyclist in front along the same route. It took the three cars 7, 8 and 14 minutes to catch up. The speed of the express train is 800 meters per minute, and the speed of the local train is 600 meters per minute. How many meters does the medium-speed train travel per minute?
Let the speed of the bicycle be x m/min.
(800-X)*7=(600-X)* 14
Found that x is 400.
So the distance is 2800 meters.
So the medium-speed car is 2800/8+400 = 750m/min.
There are three classes in a workshop with the same number of people, and the number of men in class one is equal to the number of women in class two. Boys in Class One and Class Two account for four-sevenths of the total number of boys in the workshop. It is understood that there are 75 girls in Class Three. How many people are there in this workshop?
If the total number of students is X, then because the number of students in three classes is equal, each class is X/3, the number of male workers in one class is equal to the number of female workers in two classes, the total number of male workers in one class and two classes is equal to the total number of female workers in one class, there are X-75 male workers in three classes and boys in one class and two classes. /kloc-There are 4 (X-75)/7 girls in Class 0 and Class 2, 3 (X-75)/7 boys in Class 3 and [x/3-3 (x-75)/7 girls in Class 3], so the sum of the girls in Class 3 is:
4(X-75)/7+[X/3-3(X-75)/7]=75
X= 180 total number of people
X/3=60 class size
There is no answer to find 8 fractional equation calculation problems! Baidu knows that most people answer questions and it is difficult to ask questions. I suggest you look for it in Baidu Library.
Who has 50 equations (0.5+x)+x=9.8÷2?
2(X+X+0.5)=9.8
25000+x=6x
3200=450+5X+X
X-0.8X=6
12x-8x=4.8
7.5*2X= 15
1.2x=8 1.6
x+5.6=9.4
x-0.7x=3.6
9 1÷x= 1.3
X+8.3= 10.7
15x=3
3x-8= 16
7(x-2)=2x+3
3x+9=27
18(x-2)=270
12x=300-4x
7x+5.3=7.4
3x÷5=4.8
30 \x+25 = 85
1.4×8-2x=6
6x- 12.8×3=0.06
4 10-3x= 170
3(x+0.5)=2 1
0.5x+8=43
6x-3x= 18
7(6.5+x)=87.5
Help to find the equation problem100 (2) 7x-5/4 = 3/81/4x-1/2 = 3/4 (3) 2x-1/6 = 5x+6538.
(6)2x+ 1/3-5x- 1/6 = 1
(7) 1/7(2x+ 14)=4x-2x
(8)3/ 10(200+x)-2/ 10(300-x)= 300×9/25
1.52- 12 x = 15 2。 9 1÷3.5x = 1.3 3.25 X+8.3 = 10.74。 15x =3
1.52- 12 x = 152。 9 1÷3.5x = 1.3 4。 15x = 3 3.25 X+8.3 = 10.7 2x+0.82 = 8.2 3+0.5x = 7
7.8÷x=2.6 80x÷4= 12
5-0.9x = 2.75 2x+0.4x = 48 6-2x+6x = 18 35x+ 13x = 9.6
0.52×5-4x = 0.6 0.7(x+0.9)= 42 1.3x+2.4×3 = 12.4
(3-0.5)x = 12 5x+2x = 1.4+0.07 6.25×4 = 25+4x
7x+3× 1.4x = 0.2×56 5(3-2x)= 2.4×5(2 1-5x)÷2 = x
5.4x+3.8x- 1.2x = 4.8 19x-24- 1 1x = 56
(8x-6-4x)÷2= 16 8x+2-50=5x
What is the quotient of 2.5 plus 7.5 divided by 2.5?
2.2.5 plus the sum of 7.5 divided by 2.5, what is the quotient?
3.25. 16 divided by the quotient of 3.7, minus the product of 6.2 and 0.4, what's the difference?
4. 8. 4 13.44 What is the product of the quotient divided by 0.65 and multiplied by 2.5?
5.7.2 0.8 is less than 2 times of a certain number. What is a certain number?
6. Twice a number is more than half of 4.5. Find this number.
7. The sum of five times a number and seven times this number is 156. Find this number.
8. 3.5 times a number is 46 times 65438+0.2 times this number. What's this number?
9. A number and three times is 16. What's this number?
10. The number A is 2.8, which is 0.8 less than three times the number B. What is the number B?
1 1. The difference between 3 times a number and 5 is equal to 2 times this number. Find this number.
12. Five times a number is equal to twice this number plus the sum of 1.2. What's this number?
13. The difference between a number and 4.8 is divided by 0.5, and the quotient is 36. What's this number?
What is the quotient of 2.5 plus 7.5 divided by 2.5? x+3.86 = 5.46 17.89-x = 12.89 40.8+x = 57.3 x-3.25 = 16.75
2x+0.82 = 8.2 3+0.5x = 7 7.8÷x = 2.6 80x÷4 = 12
5-0.9x = 2.75 2x+0.4x = 48 6-2x+6x = 18 35x+ 13x = 9.6
0.52×5-4x = 0.6 * 0.7(x+0.9)= 42 1.3x+2.4×3 = 12.4
(8x-6-4x)÷2= 16 8x+2-50=5x
(3-0.5)x = 12 # 5x+2x = 1.4+0.07 6.25×4 = 25+4x
7x+3× 1.4x = 0.2×56 5(3-2x)= 2.4×5(2 1-5x)÷2 = x
5.4x+3.8x- 1.2x = 4.8 19x-24- 1 1x = 56(6)= 1
;
( 1) = 1; (2) ; . (2)
(4)
(4) (3)
(9) ( 10)
( 1) (2)
(3)
( 1)(2)(x- 16)(3x+8)= 0；
(3) (4)
Do not answer 1. There are impure calcium carbonate samples, which are known to contain one or more impurities in sodium carbonate, potassium carbonate, magnesium carbonate or barium carbonate. 10g sample reacts with enough dilute hydrochloric acid to generate 4.4g carbon dioxide. So what impurities must be contained in this sample?
2. Continuously introduce hydrogen into the mixture of 5g copper powder and copper oxide, and heat it. After the full reaction, the heating was stopped, and after cooling, the mass of the residual solid was 4.2g How many grams of copper oxide and copper powder were contained in the original mixture?
3. A student put 16g copper oxide into a test tube, introduced hydrogen and heated it. After a period of reaction, the heating was stopped, and after the test tube was cooled, the mass of the remaining solid in the test tube was14.4g. How many grams of copper oxide was reduced?
4. The mixture of potassium chlorate and a small amount of manganese dioxide is heated to produce oxygen, which is used in the combustion experiment of red phosphorus. How many grams of potassium chlorate is needed to prepare phosphorus pentoxide 15g?
5. How many grams of hydrogen released by the reaction of zinc with sufficient hydrochloric acid are completely burned in chlorine gas, and 2.87 grams of precipitate can be obtained by injecting the generated hydrogen chloride into sufficient silver nitrate solution?
6. Heat a gCuO to reduce the flow of CO gas. The total mass of solid matter is called b g, and the mass of CO2 produced at the same time is called dg. It is known that the relative atomic mass of oxygen is 16, and the relative atomic mass of carbon is expressed by mathematical formula.
7. A mixture of metal Cu and CuO * * 6g exists, and after complete reduction with H2, 5.2g of Cu * * * is obtained. What is the mass fraction of Cu in the original mixture?
Whether solving equations is a calculation problem must be calculated! You're upstairs.
The elementary linear equation (calculation problem, that is, equation equation) in grade one must have an answer 1×(x+8)=( 1+x)×5.
x+8=5+5x
4x=8-5
x=3/4