The intersection of BD and AC is O. According to the meaning of the question, BOC and BOA are congruent triangles, so the arithmetic square root of ∠BAC=∠BCA, BC=2, 3 is ∠ BCD = 60. Because AB is parallel to CD, ∠BAC=∠DCA, ∠.

So BC is parallel to AD and ABCD is parallel to parallelogram.