Current location - Training Enrollment Network - Mathematics courses - Primary school mathematics discount
Primary school mathematics discount
I don't know if the title is wrong, because I asked about the biggest discount, not the biggest discount.

If you ask the maximum discount, it is equivalent to asking the maximum discount rate, 30% off.

If you ask for the highest price, it is equivalent to asking for the biggest discount.

Suppose you buy x yuan,

The amount of goods purchased exceeds that of 200 yuan, but less than that of 500 yuan,

The discount rate is (x-60)/x =1-60/x.

The topic requires a maximum discount, which is equivalent to the maximum value of the formula (1-60/x).

The maximization formula (1-60/x) requires x to be larger, because the larger the denominator, the smaller the fractional value, and the smaller the fractional value subtracted, the greater the formula result.

Because x is restricted by conditions

When x=500, the result of the formula (1-60/x) is 0.88, but x can't be 500, so the result of the formula can only be infinitely close to 0.87999999. ...

Therefore, the maximum discount is 18% when the purchased goods exceed 200 yuan but are lower than 500 yuan.

When the goods purchased exceed 500 yuan, as above, when x is infinite, the result of the formula is infinitely close to 1.

The result of the formula is 0.999 ...

At this time, the maximum discount rate is 99%.

Has the problem of fifth grade in primary school really involved the infinite concept that only middle schools have? It's not an Olympic math problem, is it?