Answer: Let the side length of a square be 300, FN=X, gn = y. ..

∠∠FBC =∠FGN =∠CDE

∴FC/BC=FN/GN=GN/DN

That is, 200/300=X/Y=Y/( 100+X)

By solving the above equation, we can get: X=80, Y= 120.

s 1:s2=(80+ 100)^2: 120^2=9:4