Kilometer/hour

rule

(x-2)* 1+(x-2)*4=(x+2)*4

solve

x= 18

Kilometer/hour

Distance s

=

(x+2)*4*2= 160

kilometre (km)

Assuming that the plane can fly out for t hours at most, it will return. The flight distance at this time is skm.

(575+25)*t=(575-25)*(4.6-t)

solve

t

=

2.2

h

s=

(575+25)*t=600*2.2= 1320

kilometre (km)

therefore

The plane can fly out of 1320 km at most and will return.