(? p→q)→(？ q∨p)

(? p→q)∨(p∨？ Q) Become a conjunction disjunction.

(p∨q)∨(p∨？ Q) Become a conjunction disjunction.

(? p∧？ q)∨(p∨？ Q) de Morgan's law

(? p∧？ q)∨p∨？ Q-associative law

q∨p∨？ Q- separation absorption rate

p∨？ Q idempotent law

Get Lord conjunctive normal form,

Check the missing largest item again.

The second part of money supply

∏(2)

∏(2)

∑(2)

The second part of money supply

(p∨q)∨？ (? p∨q)∨？ (? p∨？ Q) de Morgan's law

(? p∧？ q)∨(p∧？ Q)∨(p∧q) De Morgan's Law

Get the principal disjunctive normal form

The real task is

(p, q) = (0,0), (1, 0) or (1, 1).

Question (3)

(p∨(q∧r))→(p∨q∨r)

(p∨(q∧r))∨p∨q∨r

(? p∧？ (q∧r))∨p∨q∨r De Morgan's Law

(q∧r)∨p∨q∨r absorption rate

q∨？ R∨p∨q∨r De Morgan's Law

T yongzhen