Copying the wrong constant term means that the main term and the secondary term are correct.

That is, (x-8)(x-2)=0.

X 2-10x of X 2- 16 is right+10x is wrong.

Let's set the constant term to k.

x^2- 10x+k=0

B copied the wrong item again.

The main term of error is d.

x^2+dx+k=0

Replace x 1=-9, x2=- 1.

get

{8 1-9d+k=0

{ 1-d+k=0

solve

{k=9

{d= 10

The wrong equation is x 2+ 10x+9 = 0.

Substitute the correct k into the above X 2- 10x.

The original equation should be x 2-10x+9 = 0.

(x- 1)(x-9)=0

x 1= 1，x2=9

If you don't understand, please ask. Have a good time O(∩_∩)O~