1. The year before last, computers A and B sold computers X and Y respectively.

x+y=2200 x=2200-y( 1)

X (1+6%)+y (1-5%) = 2200+10, that is,1.06x+0.95y = 2310.

b

Substituting 1 into 2 gives: 2332-1.06y+0.95y = 2310.

22=0. 1 1y

Y=200 units. So x=2000 units.

2. Let the distance between two cities be s kilometers.

Because: it takes 17/6h to fly with the wind and 3h to fly against the wind.

So the downwind speed is 6s/ 17, and the headwind speed is s/3.

And because the wind speed is 24 km/h.

So: 6s/ 17-s/3=24x2 (the speed difference between forward and reverse is just twice the wind speed).

s/5 1=48

S = 2448km km

3. Suppose that when T was a child, two cars met. Then:

(45+36)t= 108

8 1t= 108

T=4/3 hours means: 1 hour for 20 minutes.

So the meeting time is:16+1:20 =17: 20.