The remaining bullets are only the number of one person, three people and three bullets.
So we used twice as many bullets as the rest.
There are six bullets left, that is, six bullets per person.
The hunter used two bullets, so the remaining bullets were the number of one person.
The number of remaining bullets is 12/2=6.
The remaining amount is the amount each of them takes: 6.
(2+ 1+ 1)×3÷2=6 (hair)
Two sets of equations assume that x, y and z meters are fixed on the first day, the second day and the third day respectively.
x :y = 5 :6 ( 1)
y :z = 2 :3 (2)
x + y + z = 140 (3)
Equation (1) can be simplified as 6x=5y (4).
(2) The formula can be simplified as 3y=2z, that is, y=(2/3)z (5).
Substituting Equation (5) into Equation (4) can get x=(5/9)z (6).
Substitute Formula (5) and Formula (6) into Formula (3).
That is, (5/9)z+(2/3)z+z = 140.
Z = 63 can be obtained by simplifying the calculation.
By this time, we have calculated that 63 meters have been built on the third day.
We can continue to know how many meters were built on the first day and the second day.
Substitute z = 63 into equation (5) and equation (6) respectively.
Finally, x = 35 y=42.
The first day is 35 meters, and the second day is 42 meters.