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Comprehensive Exercise 2 of Mathematics Target Detection in Grade Six (Part One)
The area of this circle is () square centimeters.

Let the radius of this circle be R.

The approximate rectangle has a length equal to half of the circumference and a width equal to the radius of the circle.

therefore

[(2πR/2)+R]*2-2πR=6

(πR+R)*2-2πR=6

2πR+2R-2πR=6

2R=6

R=3

Area of a circle

=πR*R

=π*3*3

=9π

=28.26 square centimeters