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The Application of Quadratic Function in Mathematics of Grade Three.
Solution: when the selling price is x, the maximum profit is obtained, and the maximum profit is y.

∴ The daily sales volume is100-(x-10) *10.

∴y=[ 100-(x- 10)* 10]*x-[ 100-(x- 10)* 10]*8

=[ 100-(X- 10)* 10](X-8)

=- 10X^2+280X- 1600

=- 10(X- 14)^2+360

∴ The opening direction of parabola is downward, and the equation of symmetry axis is X= 14.

∴ when X= 14, y gets the maximum value of 360, that is, when the selling price is 14 yuan, it gets the maximum profit 360 yuan.

Answer: When the price is 14 yuan, the maximum profit is obtained, and the maximum profit is 360 yuan.