1.4x-2y+3=0, then y=2x+ 1.5 Because the coefficients of x are the same, but the constants are different, the two straight lines are parallel.

2. Change the equation into the form of y=kx+b by the above method. As long as the two equations are the same in k and different in b, the two lines are parallel. So you may have written this question wrong, but I didn't find it.

3. There is nothing in common, that is, two straight lines are parallel or two straight line equations do not have the same solution. Ditto. Choose D.

4. If the distance from the X axis is 3, then Y=+3 or -3, and D is selected.

5. let the equation be y = kx+b.

(1) passes through (-2,3) a straight line parallel to X=3, that is, X=-2.

(2)Y=3

(3)2x+y-3=0 y=-2x+3, so k=-2. Substitute the point into 3 =-2 *(2)+b, and b =- 1.

So the equation is y=-2x- 1.

Boss, don't you know any of these questions?