Senior one mathematics (key) reference answer and grading standard

First, multiple choice questions

The title is 1 23455 6789 10.

Answer B D C B A A D C A C

Second, fill in the blanks

11.(1,1,)12.y = 2x or x+y-3 = 013.13cm/kloc-0.

Third, answer questions.

16. solution: the coordinate of point d in line segment AB is (0, -4).

Therefore, the equation of the midline of the line segment AB is ...................................................................................................................................................................

Simultaneous equations, the solution is 4 points.

Therefore, the coordinates of the center of the circle are C (- 1, -2), 5 points.

Radius, 7 o'clock.

Therefore, the standard equation of this circle is 8 points.

17.( 1) Solution: If the intersection of BC 1 and B 1C is at point F, then F is the point in BC 1.

D is the midpoint of AB ∴ DF ‖ ACL, and ................................................................... is 2 points.

∫DF plane B 1DC, ACl plane B 1DC.

∴AC 1‖ surface b 1dc 5 points.

(2) According to the meaning of the question, the catch is a cube with a side length of 2 ... 7 points.

Its diameter is 8 o'clock.

So 10 points.

18. solution: (1) let A (a, a), and the midpoint between a and b is p,

B (2-a,-a) ..............................1min.

(2-a)+3(-a)=0, the solution is a =, and ................................................................................................................... has 2 points.

A (,), B () ... 3 points.

The straight line AB is y =(- 1-)(x- 1)5 points.

(2) The distance from point A and point B to L: mxy+2 = 0 is equal.

= ……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………

M =- 1- or m = 2 ...............................................................10.

19. Solution: (1) From the meaning of the question, the center of the circle is in a straight line, and ........................................... scores 2 points.

So the center of the circle is the midpoint, four points.

The equation for circle c is

(2) (key) Let the equation of the line where the ray is located be, and substitute:

, ... 6 points.

The intersection of a ray and a straight line has the same symbols as 3 points and 7 points.

=

= ... 9 points.

No minimum value 10 integral.

20. Solution: (1) Because the three sides AB, AC and AD of the triangular pyramid A-BCD are perpendicular to each other, namely AB ⊥ AC and AB ⊥ AD.

So AB⊥ plane ACD has three points.

It can also be proved that plane ACD⊥ plane ABC, plane ABD⊥ plane ABC.

So ABC, ABD and ACD are perpendicular to each other ... 6 o'clock.

(2) Because ................... 10.

∴ In a triangular pyramid A-BCD, if three sides ABC, ABD and ACD are perpendicular to each other, then these three sides

The sum of the squares of the areas is equal to the square of the bottom area, that is, 12 points.

2008-2009 school year second semester Nanchang final examination paper.

Reference answers and grading standards of mathematics in senior one.

First, multiple choice questions

The title is 1 23455 6789 10.

Answer B D C B A A D C A C

Second, fill in the blanks

11.12.y = 2x or x+y-3 = 0.13.13cm14.x+2y-3 = 0./kloc. ②.

Third, answer questions.

16. solution: the coordinate of point d in line segment AB is (0, -4).

Therefore, the equation of the midline of the line segment AB is ...................................................................................................................................................................

Simultaneous equations, the solution is 4 points.

Therefore, the coordinates of the center of the circle are C (- 1, -2), 5 points.

Radius, 7 o'clock.

Therefore, the standard equation of this circle is 8 points.

17.( 1) Solution: If the intersection of BC 1 and B 1C is at point F, then F is the point in BC 1.

D is the midpoint of AB ∴ DF ‖ ACL, and .................................................................... is 2 points.

∫DF plane B 1DC, ACl plane B 1DC.

∴AC 1‖ surface b 1dc 5 points.

(2) According to the meaning of the question, the catch is a cube with a side length of 2 ... 7 points.

Its diameter is 8 o'clock.

Therefore, ............................ 10.

18. solution: (1) let A (a, a), and the midpoint between a and b is p,

B (2-a,-a) .............................1min.

(2-a)+3(-a)=0, the solution is a =, and ................................................................................................................ has 2 points.

A (,), B () ... 3 points.

The straight line AB is y =(- 1-)(x- 1)5 points.

(2) The distance from A and B to L: MX-Y+2 = 0 is equal.

= ……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………

M =- 1- or m =-2 ................................................10.

19. Solution: (1) From the meaning of the question, the center of the circle is in a straight line, and ...................................... scores 2 points.

So the center of the circle is the midpoint, four points.

The equation for circle c is

(2)

Seven points

Substitute it into the above formula and get 9 points.

................................ 10.

20. Solution: (1) Because the three sides AB, AC and AD of the triangular pyramid A-BCD are perpendicular to each other,

That is, AB⊥AC, AB⊥AD,

So AB⊥ aircraft ACD ....................................................................................................................................................................

It can also be proved that plane ACD⊥ plane ABC, plane ABD⊥ plane ABC.

So ABC, ABD and ACD are perpendicular to each other ... 6 o'clock.

(2) If AB=AC=AD=a, then ... 8 points.

, ... 9 points.

So the total area of the triangular pyramid: s total =S side +S bottom = ...................