A=0。 Then x+ 1 < 0, x

Answer ≠0. Then the quadratic function. Two are [a-1√ (a2-6a+1)]/2a. Of course, we should also consider whether there is a solution.

Continue to classify: a.a > 0.

(1) If there is a root, that is, (a-3) 2 > 8, that is, between a > 3+2 √ 2 or 3-2 √ 2 > A > 0. [a- 1-√(a^2-6a+ 1)]/2a 3-2 √ 2。 Then x has no solution.

B.a a > 0。 Then [a-1-√ (a2-6a+1)]/2a < xa > 3-2 √ 2. Then x has no solution.

a>3+2√2。 [a- 1-√(a^2-6a+ 1)]/2a