Let 2/(x 2-1) = a/(x+1)+b/(x-1).

Right component = [a (x-1)+b (x+1)]/(x 2-1) = [(a+b) x+(b-a)]/(x 2-/kloc-

Comparing the molecule on the right with the molecule on the left, we get:

A+b=0 and b-a=2, then the solution is B = 1 and A =- 1.

So the right =-1/(x+1)+1(x-1) =1/(x-1)-1(x