7/ 12x*(x+ 10)=x+2
x=9.2
4. solution: suppose that the price of this commodity is x yuan per piece.
0.9x-250=250* 15.2%
x=320
5. Solution: Let each box have X products.
(8x+4)/5 =( 1 1x+ 1)/7+ 1
(8x+4)* 7 =( 1 1x+ 1)* 5+35
56x+28 = 55x+5+35
56x-55x=40-28
x = 12
6. solution: suppose x hours later.
30+20x=90- 10x
20x+ 10x=90-30
30x=60
x=2
Speed:
30+20*2
=30+40
=70 km/h
7.( 1) Let the per capita quota of this month be X pieces.
(4x+20)/4=(6x-20)/5
x=45
(2) Let the per capita quota of this month be X pieces.
(4x+20)/4=(6x-20)/5+2
x=35
(3) Let the per capita quota of this month be X pieces.
(4x+20)/4=(6x-20)/5-2
x=55
8.( 1) Let the speed of the first section be x.
5x+5 *(x+20)+5 *(x+20- 10)= 1262
x=74
The speed of the second section is 74+20=94 kilometers per hour.
The speed of the third section is 74+20- 10=84 kilometers per hour.
(2)8 hours' journey =74*5+94*(8-5)=652 kilometers.
In the map scale problem, I was not set to I.
652I represents the distance from Beijing on the map.
9.( 1).84 (2).38 (3).80
The area of trapezoid [teaching goal]
1, through the operation activities, experienced the pro