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Reflections on solving problems in mathematical poetry
Should it be 13 songs? Did the questioner type the question wrong?

Option 1: If the five-character quatrains of 13 are removed, the number of the first two poems is equal, and the number of words is different at this time.

13×5×4+20=280 (word).

Every song has a different number of words.

7×4-5×4=8 (word).

Therefore, the seven-character quatrain is

280(28-20)= 35 (first).

The five-character quatrain is

35+ 13=48 (first).

A: There are 48 five-character quatrains and 35 seven-character quatrains.

Solution 2: Suppose there are 23 five-character quatrains, then according to the difference of 13, the seven-character quatrains are 10. The number of words is 20×23=460 (words), 28× 65,438+00 = 280 (words), but there are more words in five-character quatrains.

460-280= 180 (word).

It is different from "20 words less" in the title.

180+20=200.

Explain that the number of hypothetical poems is small. In order to keep the difference between 13 poems, a five-character quatrain and a seven-character quatrain were added, and the word difference increased by 8. So the number of five-character quatrains is more than assumed.

200÷8=25 (first).

The five-character quatrain is

23+25=48 (first).

The seven-character quatrain is

10+ ... should be 13 songs? Did the questioner type the question wrong?

Option 1: If the five-character quatrains of 13 are removed, the number of the first two poems is equal, and the number of words is different at this time.

13×5×4+20=280 (word).

Every song has a different number of words.

7×4-5×4=8 (word).

Therefore, the seven-character quatrain is

280(28-20)= 35 (first).

The five-character quatrain is

35+ 13=48 (first).

A: There are 48 five-character quatrains and 35 seven-character quatrains.

Solution 2: Suppose there are 23 five-character quatrains, then according to the difference of 13, the seven-character quatrains are 10. The number of words is 20×23=460 (words), 28× 65,438+00 = 280 (words), but there are more words in five-character quatrains.

460-280= 180 (word).

It is different from "20 words less" in the title.

180+20=200.

Explain that the number of hypothetical poems is small. In order to keep the difference between 13 poems, a five-character quatrain and a seven-character quatrain were added, and the word difference increased by 8. So the number of five-character quatrains is more than assumed.

200÷8=25 (first).

The five-character quatrain is

23+25=48 (first).

The seven-character quatrain is

10+25=35 (first).