Suppose the advertisement can be played x times, 15 seconds;

x * 0.6+(2 * 60- 15 * x)/30 * 1 = 4.4；

The solution is x = 4；;

Then the times of advertising in 30 seconds are: (2*60- 15*4)/30=2 times;

Question 2:

All 15 advertisements can be played 8 times; All 30 advertisements can be published 4 times;

Play 1 30 second advertisement: you can play 15 advertisement 6 times: the income is 46,000.

Play two 30-second advertisements: you can play four 15 advertisements: the income is 44000.

Play three 30-second advertisements: you can play two 15 advertisements: the income is 42,000.

So there are three arrangements: broadcast 1 30 second advertisement; you can broadcast 15 advertisement 6 times, and the highest income is 46,000.