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Mathematical prohibition problem
If the number of people who failed is X, then the number of people who passed is 3x+ 14.

5x=3x+ 14+32

5x=3x+46

(5-3)x=46

x=23,3x+ 14=83

83+23= 106 (person)

So * * * has 106 participants.

2. Because ABCDEF and BCDEFA are both 6 digits.

Available A≤3

3F=A,F= 1,A=3。

The number at the end of 3E is 1, so E=7.

The number at the end of 3D+2 is 7, so D=5.

3C+ 1 has a number 5 at the end, so C=8.

The number at the end of 3B+2 is 8, so B=2.

Therefore, this solution does not hold water.

3F=A,F=7,A= 1。

The number at the end of 3E+2 is 7, so E=5.

The number at the end of 3D+ 1 is 5, so D=8.

The number at the end of 3C+2 is 8, so C=2.

3B ends with 2, so B=4.

So the solution holds, and the new number is 42857 1.

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