S=20

Because the original coordinate of c is (3,3), it is obtained from known conditions, (3-2,3-5);

The picture is better. Draw it on the map and count the squares.

Note: I am too lazy to write. The first question is copied from L 1.

Two: You didn't give me the data, so one cell is the square of 1× 1.

The first sweep should be the original area plus a 3×5 rectangle, which is 3×2÷2+3×5= 18.

The second scan is because the small triangle behind point C has been scanned, so the second scan should be a 2×2÷2 triangle plus a 2×2 square, which is 2×2÷2+2×2=6.

Add up to 6+ 18=24.