Assign three jobs to five employees. If each employee can get more than one job, how many different ways are there?
Junior, you are trapped by this topic, which is translated from the English version of Discrete Mathematics and its Application. The topic "If every employee can get more than one job" is a supplementary condition, not a restrictive condition. The title means "allowing" every employee to get all kinds of jobs. So you understand that work is the domain of definition and employees are the mapping of partner domain. The third power of 5 = 125.