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Mathematical problem: find the area of an irregular quadrilateral
Connecting AC, triangle ABC is a right triangle with an area of 3×4÷2=6cm?

And AC=5cm (Pythagorean theorem)

AD= 12, CD= 13, so △ACD is a right triangle with an area of 5× 12÷2=60cm?

The total area is 6+60=66cm?

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