If the intersection point F is FG⊥BC and the extension line of intersection point CB is at G, then ∠ FGB = 90; from AF⊥AC, then ∠ FAC = 90 and ∠ ACB = 90, so the quadrilateral ABGF is rectangular;

Because AD⊥AB, AF⊥AC, so ∠FAC=∠DAB, so ∠FAB=∠DAC, AD=AB,

According to the nature of graph rotation, the quadrangle ABGF with AC = AF is a rectangle, so the quadrangle ABGF is a square.

So: AF=AG, while FG⊥BC, AF⊥AC, so: CF shares ∠ACB equally.