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Eighth grade, the second volume of mathematics, seeking answers from the gods ~
There are two situations,

∠∠BHD =∠AHE, and ∠∠ AEH =∠ ADC = 90,

∴∠DAC+∠C=90,∠HAE+∠AHE=90,

∴∠AHE=∠C,

∴∠C=∠BHD,

BH = AC,∠HBD=∠DAC,∠C=∠BHD,

∴△HBD≌△CAD,

∴AD=BD.

As shown in figure (1) ∠ ABC = 45;

As shown in figure (2), ∠ ABC = 135.

∵AD=BD,AD⊥BD,

△ ADB is an isosceles right triangle,

∴∠ABD=45,

∴∠ABC= 180 -45 = 135,

So the answer is: when H is inside △ABC 45 or when H is outside △ABC 135.

(Because pictures can't be uploaded, you can draw them yourself ~)