Let h (x) = ax 2+bx+c (a, b and c are rational numbers).

Substitute a for h (a) = a * (θ+2) 2 * (θ-1) 2/4+b * (θ+2) * (θ-1)+C.

=θ

Then calculate (θ+2) * (θ- 1) 2 =-8.

Substitution is simplified as-2a * (θ+2)+b * (θ+2) * (θ-1)+c = θ.

If b is not equal to 0, assume θ 2+pθ+q = 0 (p, q is a rational number).

It is easy to prove that it doesn't exist.

So b=0 gives-2a * (θ+2) = θ-C.

Because θ is an irrational number, in order for the equation to hold.

So a=- 1/2 c=-2.

So h(0)=c=-2.