Analysis ~ time = distance/speed, when walking 2/5 distance, cycling has already completed the whole journey, and the speed difference has walked 3/5 distance.

Walking speed: speed difference = 2: 3.

Walking speed =120× 2/3 = 80m/min = 0.08km/min.

Question 2:

Analysis ~ The first time they met, the two cars walked the whole journey, and the second time they met, the two cars walked the whole journey.

That is, from the first time to the second time, the distance traveled by the two cars is twice that of the first encounter.

According to the meaning of the question, from the first time to the second time, car B left.

75+65 =140km,

So the first time we met, the B car left.

140/2 = 70km

Whole journey = 75+70 = 145km.

Question 3:

Analysis ~

Ship speed+current speed = downstream

Ship speed-current = countercurrent

Ship speed = (15+12)/2 =13.5km/h.

Speed =15-13.5 =1.5 km/h.

Ship speed × downstream time+flow velocity ×6= ship speed × countercurrent time.

Ship speed × time difference = current speed ×6

Time difference = 1.5×6/ 13.5=2/3 hours =20 minutes.

6 hours =360 minutes

Countercurrent time =(360+20)/2= 190 minutes.

12×190/60 = 38km

Question 4:

According to the meaning of the question, the second car will be on the B side of the midpoint, and the second car will be faster than the first car.

So the first encounter was on the A side, that is, the first encounter between cars was 75 kilometers.

Referring to the first question, during the first and second encounters, a car traveled 75×2= 150 km.

75+ 150 = 225km, which is less than the whole journey (1+ 1/2) 15km.

Whole journey = (225-15) ÷ 3/2 =140km.

Question 5:

15 minute drive, took 9 minutes, and there is still the whole journey.

1-9/ 15=2/5

A 40-minute walk takes two-fifths of the journey.

40×2/5= 16 minutes

16+9=25 minutes

Question 6:

Time interval between two encounters: 22-6= 16 minutes.

That is, within 16 minutes, A walked 400 meters more than B.

Then six minutes later, A chased B.

400× 6/16 =150m