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Intersection and parallel lines in seventh grade mathematics. have
Proof: since ∠ 1=∠2 and ∠5=∠C, ∠1+∠ 5 = ∠ 2+∠ c;

So ∠ A = ∠ 2+∠ C;

Because ∠4+∠2+∠C= 180.

And because ∠3=∠4, so AD ∠ BC (internal dislocation angles are equal and two straight lines are parallel).

So ∠A+∠B= 180.

And because it has been proved that ∠ A = ∠ 2+∠ C;

So ∠ b = ∠ 4;

So AB‖DE (same angle, two straight lines are parallel)