Let the L equation be y=k(x-3), then its midpoint with 2x-y-2=0 and x+y+3=0 is p (3,0).

Therefore, according to 2x 1-k (x 1-3)-2 = 0, x2+k (x2-3)+3 = 0, x 1+x2 = 6, and k=8.

The linear equation is y=8(x-3).

15.

Axisymmetric points A'(-2, -3) and B(5, 7) about x are all on the reflected light line,

So the equation of reflected light is: y+3=(7+3)/(5+2)*(x+2).

The arrangement is 3x-7y- 1=0.

The incident ray is symmetrical about X axis, and the equation is 3x+7y- 1=0.

17.

Let the demand point be (-2y, y), then

(-2y)^2+y^2=(-3)^2/( 1^2+2^2)

Y = 3/5, so the p coordinate is (-6/5, 3/5) or (6/5, -3/5).