So the total distance of A is eastward plus the tangent length ***3x km.
Assuming that A walks y kilometers to the east, then A walks (3x-y) kilometers in the tangential direction;
For the triangle formed by the tangent and the east and north directions, we can know it by the proportional relationship of similar right-angled triangles.
Village radius /B distance traveled = distance traveled eastward/distance traveled tangent.
That is, R/x=y/3x-y, so y=9x/(x+3).
According to the right angle △ Pythagorean theorem, it is concluded that x square +y square =(3x-y) square.
So the square of x +[9x/(x+3)] is the square of (3x) [1-3/(x+3)].
That is 4x squared -3x-45=0.
So x= 15/4 or -3 (truncation)
So A and B meet at a distance of 15/4 km from the center of true north.