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Challenge mathematics content
Being divisible by 99 means being divisible by 9 and being divisible by 1 1 respectively.

Numbers divisible by 9 add up to multiples of 9.

A number divisible by 1 1 After adding every other bit, the subtraction is 0 or a multiple of 1 1.

(1) The sum of all the numbers is 12+x+y, which is a multiple of 9.

(2) The sum of every two positions is 6+X and 6+Y respectively, and the subtraction is x-y..

Since both x and y are natural numbers, the subtraction cannot be a multiple of 1 1, but only 0, so x = y.

In addition, 12+x+y is a multiple of 9, so we can know that x=y=3.

The y power of x is the third power of 3, which is equal to 27.